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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Trigonometric Equations

NTA Abhyas 2020 · Mathematics · Trigonometric Equations

If 0 ≤ x ≤ 2π, then the number of real values of x satisfying the...

If 0≤x≤2π,0 \le x \le 2\pi, then the number of real values of xx satisfying the equation 81sin2x+81cos2x=308{1}^{si{n}^{2}x} + 8{1}^{co{s}^{2}x} = 30 isIf 0 ≤ x ≤ 2π, then the number of real values of x satisfying the equation 8 1 ^ si n ^ 2 x + 8 1 ^ co s ^ 2 x = 30 is

Correct answer

8

Step-by-step solution

Let 81sin2x=t8{1}^{si{n}^{2}x} = t,

then, 81cos2x=811−sin2x=81t8{1}^{co{s}^{2}x} = 8{1}^{1 - si{n}^{2}x} = \dfrac{81}{t}
So, the given equation is t+81t=30t + \dfrac{81}{t} = 30
t2–30t+81=0{t}^{2} – 30t + 81 = 0 ⇒t=3⇒ t = 3 or 2727
81sin2x=8{1}^{si{n}^{2}x} = 33 or 2727
⇒⇒ 34sin2x=31{3}^{4si{n}^{2}x} = {3}^{1} or 33{3}^{3}
⇒sin⁡2x=14⇒ \sin^{2} x = \dfrac{1}{4} or 34⇒sinx=±12,±32\dfrac{3}{4} ⇒ sin x = \pm \dfrac{1}{2}, \pm \dfrac{\sqrt{3}}{2}
If 0 ≤ x ≤ 2π, then the number of real values of x satisfying the equation 8 1 ^ si n ^ 2 x + 8 1 ^ co s ^ 2 x = 30 is
Hence, there are 88 solutions between 00 and 2π2\pi.

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