The number of values of x in the interval 0 , 5 π satisfying the equation 3 sin 2 ⁡ x - 7 sin ⁡ x + 2 = 0 is

Step-by-step solution

3 sin 2 ⁡ x - 7 sin ⁡ x + 2 = 0 3 sin 2 ⁡ x - 6 sin ⁡ x - sin ⁡ x + 2 = 0 3 sin ⁡ x - 1 sin ⁡ x - 2 = 0 ⇒ sin ⁡ x = 1 3 , sin ⁡ x = 2 not possible Fro the figure, 6 roots in 0 , 5 π