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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

A smooth sphere is moving on a horizontal surface with a velocity vector 2 i ^ + 2 j ^ m s - 1 immediately before it hits a vertical wall. The wall is parallel to the vector j ^ and the coefficient of restitution between the sphere and the wall is e = 1 2 . The velocity of the sphere, after it hits the wall, is

Options

  1. Ai ^ - j ^
  2. B- i ^ + 2 j ^
  3. C- i ^ - j ^
  4. D2 i ^ - j ^

Correct answer

B. - i ^ + 2 j ^

Step-by-step solution

1 2 = 0 - v x 2 v x = - 1 v → = - i ^ + 2 j ^

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