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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NTA Abhyas 2020 · Physics · Center of Mass, Momentum and Collision

A smooth sphere is moving on a horizontal surface with a velocity...

A smooth sphere is moving on a horizontal surface with a velocity vector \left(2\overset{^}{i} + 2\overset{^}{j}\right)ms^{- 1}~immediately before it hits a vertical wall. The wall is parallel to the vector \overset{^}{j}~and the coefficient of restitution between the sphere and the wall is e=12e = \dfrac{1}{2}. The velocity of the sphere, after it hits the wall, is

A smooth sphere is moving on a horizontal surface with a velocity vector (2 ^ i + 2 ^ j )ms^ - 1 ~immediately before it

Options

  1. A\overset{^}{i} - \overset{^}{j}
  2. B- \overset{^}{i} + 2 \overset{^}{j}
  3. C- \overset{^}{i} - \overset{^}{j}
  4. D2 \overset{^}{i} - \overset{^}{j}

Correct answer

B. - \overset{^}{i} + 2 \overset{^}{j}

Step-by-step solution

12=0−vx2\dfrac{1}{2} = \dfrac{0 - {v}_{x}}{2}

vx=−1{v}_{x} = - 1

\overset{→}{v} = - \overset{^}{i} + 2\overset{^}{j}

A smooth sphere is moving on a horizontal surface with a velocity vector (2 ^ i + 2 ^ j )ms^ - 1 ~immediately before it
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