A ball of mass m moving with a velocity v strikes the bob of a pendulum at rest. The mass of the bob is also m . If the collision is perfectly inelastic, the height to which the bob will rise is given by h = v ^ 2 x · g

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Correct answer: 8

Because the collision is perfectly inelastic, the two blocks stick together. By conservation of linear momentum,

2mV = mv

or

V = \dfrac{v}{2}

By conservation of energy,

2mgh = \dfrac{1}{2} \times 2m{V}^{2}

or

h = \dfrac{{v}^{2}}{8 \cdot g}

A ball of mass m moving with a velocity v strikes the bob of a...

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