NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice
The masses of five balls at rest and lying at equal distances in a straight line are in geometrical progression with ratio 2 and their coefficients of restitution are each 2 3 . If the first ball be started towards the second with velocity u , then the velocity communicated to 5 th ball is
Options
- A5 9 u
- B5 9 2 u
- C5 9 3 u
- D5 9 4 u
Correct answer
D. 5 9 4 u
Step-by-step solution
We know that velocity of 2nd ball after collision is given by v 2 = u 1 1 + e m 1 ( m 1 + m 2 ) + u 2 ( m 2 - m 1 e ) ( m 1 + m 2 ) In present problem u 2 = 0 , m 2 = 2 m 1 and , hence v 2 = u 1 + 2 3 m 1 ( m 1 + 2 m 1 ) = 5 9 u As four exactly similar type of collisions are taking place successively, hence velocity communicated to fifth ball v 5 = 5 9 4 u