A body of mass m moving with velocity v collides head-on elastically with another body of mass 2m which is initially at rest. The ratio of K . E . of mass m before and after the collision will be

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Correct answer: 9

K . E . of the colliding body before the collision = (1)/(2)m v ^ 2 After collision its velocity becomes v ^ ' = ( m _ 1 - m _ 2 ) ( m _ 1 + m _ 2 ) v = (m)/(3m)v = (v)/(3) ∴ K . E . after collision (1)/(2)m v ^ '2 = (1)/(2) m v ^ 2 9 The ratio of kinetic energy = K. E _ before K.E _ after = (1)/(2)m v ^ 2 (1)/(2) m v ^ 2 9 = 9: 1

A body of mass m moving with velocity v collides head-on...

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