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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NTA Abhyas 2020 · Physics · Center of Mass, Momentum and Collision

In the diagram shown, no friction at any contact surface....

In the diagram shown, no friction at any contact surface. Initially, the spring has no deformation. What will be the maximum deformation in the spring? Consider all the strings to be sufficiently large. Consider the spring constant to be KK.

In the diagram shown, no friction at any contact surface. Initially, the spring has no deformation. What will be the

Options

  1. A4F3K\dfrac{4F}{3K}
  2. B8F3K\dfrac{8F}{3K}
  3. CF3K\dfrac{F}{3K}
  4. DNone

Correct answer

B. 8F3K\dfrac{8F}{3K}

Step-by-step solution

In the diagram shown, no friction at any contact surface. Initially, the spring has no deformation. What will be the

aCOM=F3M{a}_{COM} = \dfrac{F}{3M}

with respect to the Center of mass

In the diagram shown, no friction at any contact surface. Initially, the spring has no deformation. What will be the

4F3X1+4F3X2=12K(X1+X2)2\dfrac{4F}{3}{X}_{1} + \dfrac{4F}{3}{X}_{2} = \dfrac{1}{2}K \left({X}_{1} + {X}_{2}\right)2

\dfrac{8F}{3K} = \left({X}_{1} + {X}_{2}\right)
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