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An isolated particle of mass m is moving in the horizontal plane x , y along the x -axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m 4 and 3 m 4 . An instant later, the smaller fragment is at y = + 15 cm . The larger fragment at this instant is at

Options

  1. Ay = - 5   cm
  2. By = + 20   cm
  3. Cy = + 5   cm
  4. Dy = - 20   cm

Correct answer

A. y = - 5   cm

Step-by-step solution

Before the explosion, the particle was moving along x -axis i.e., it has no y -component of velocity. Therefore, the centre of mass will not move in y -direction or we can say y cm = 0 . Now, y cm = m 1 y 1 + m 2 y 2 m 1 + m 2 Therefore, 0 = m / 4 + 15 + 3 m / 4 y m / 4 + 3 m / 4 or, y = - 5   cm

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