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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NTA Abhyas 2020 · Physics · Center of Mass, Momentum and Collision

A 12 kg bomb at rest explodes into two pieces of 4 kg and 8 kg. If...

A 1212 kg bomb at rest explodes into two pieces of 44 kg and 88 kg. If the momentum of 44 kg piece is 20Ns20Ns, the kinetic energy of the 88 kg piece is

Options

  1. A25J25J
  2. B20J20J
  3. C50J50J
  4. D40J40J

Correct answer

A. 25J25J

Step-by-step solution

The explosion is due to internal forces so the momentum of the system is conserved.

Applying conservation of momentum,

0=m1v+m2v′0=20+8v′0 = {m}_{1}v + {m}_{2}v′0 = 20 + 8v′

v′=−208=−52ms−1v′ = \dfrac{- 20}{8} = \dfrac{- 5}{2}ms^{- 1}

After the explosion,

Then, KE=12mv′2KE = \dfrac{1}{2}mv{′}^{2}

=12×8×(52)2=12×8×254=25J= \dfrac{1}{2} \times 8 \times \left(\dfrac{5}{2}\right)^{2} = \dfrac{1}{2} \times 8 \times \dfrac{25}{4} = 25J
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