In optical communication systems operating at 1200nm , only 2 % of the source frequency is available for TV transmission having a bandwidth of 5MHz . The number of TV channels that can be transmitted is 10 ^ n . The

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Correct answer: 6

The frequency of optical communication is given by,

v = \dfrac{c}{\lambda}

or

v = \dfrac{3 \times {10}^{8}}{1200 \times {10}^{- 9}}

v = 25 \times {10}^{13}Hz

But only

2 %

of the source frequency is available for TV transmission.

{v}^{′} = 2 .5 \times {10}^{14} \times 2%

{v}^{′} = 2 .5 \times {10}^{14} \times \dfrac{2}{100}

{v}^{′} = 5 \times {10}^{12}Hz

∴ Numberofchannels = \dfrac{{v}^{′}}{bandwidth}

Noofchannels = \dfrac{{5 \times 10}^{12}}{{5 \times 10}^{6}} = {10}^{6} = 1million

In optical communication systems operating at 1200nm , only 2 % of...

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