NTA Abhyas JEE Main2020PhysicsCommunication SystemPractice
1 % of 10 12 Hz of a satellite link was used for telephony. The number of channels or subscribers if each channel is of 8 kHz are
Options
- A2.5 × 10 7
- B1.25 × 10 6
- C2.5 × 10 8
- D1.25 × 10 8
Correct answer
B. 1.25 × 10 6
Step-by-step solution
According to the question 1 % of 10 12 H z = 10 10 H z Number of channels = 10 10 8 × 10 3 = 1.25 × 10 6