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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Communication System

NTA Abhyas 2020 · Physics · Communication System

1% of 10 ^ 12 Hz of a satellite link was used for telephony. The...

11% of 1012Hz{10}^{12}Hz of a satellite link was used for telephony. The number of channels or subscribers if each channel is of 8kHz8kHz are

Options

  1. A2.5×1072.5 \times {10}^{7}
  2. B1.25×1061.25 \times {10}^{6}
  3. C2.5×1082.5 \times {10}^{8}
  4. D1.25×1081.25 \times {10}^{8}

Correct answer

B. 1.25×1061.25 \times {10}^{6}

Step-by-step solution

According to the question

11% of 1012Hz=1010Hz{10}^{12}Hz = {10}^{10}Hz

Number of channels =10108×103=1.25×106= \dfrac{{10}^{10}}{8 \times {10}^{3}} = 1.25 \times {10}^{6}
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