In optical communication system operating at 1200 nm , only 2 % of the source frequency is available for TV transmission having a bandwidth of 5 MHz . The number of TV channels that can be transmitted is

Step-by-step solution

The frequency optical communication v = c λ o r v = 3 × 10 8 1200 × 10 - 9 v = 25 × 10 13 H z But only 2% of the source frequency is available for TV transmission v ′ = 2.5 × 10 14 × 2 % Or v ′ = 2.5 × 10 14 × 2 100 Or v ′ = 5 × 10 12 H z ∴ N u m b e r o f c h a n n e l s = v ′ b a n d w i d t h Or N o o f c h a n n e l s = 5 × 10 12 5 × 10 6 = 10 6 = 1 m i l l i o n