NTA Abhyas JEE Main2020PhysicsCommunication SystemPractice

A signal wave of frequency 12 kHz is modulated with a carrier wave of frequency 2.51 MHz. The upper and lower side band frequencies are respectively

Options

A2512 kHz and 2508 kHz
B2522 kHz and 2488 kHz
C2522 kHz and 2498 kHz
D2512 kHz and 2488 kHz

Correct answer

C. 2522 kHz and 2498 kHz

Step-by-step solution

Upper side band (USB) frequency = f c + f m = 2.51 M H z + 12 k H z = 2510 + 12 k H z = 2522 k H z Lower side band (LSB) frequency = f c - f m = 2.51 M H z - 12 k H z = 2510 - 12 k H z = 2498 k H z

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