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In Wheatstone bridge, four resistors of resistances 15   Ω , 12   Ω , 4 Ω and 10   Ω respectively, are connected in cyclic order. The resistance (in Ω ) that is to be connected in parallel with the resistance of 10   Ω to balance the network is

Correct answer

10

Step-by-step solution

10 R 10 + R × 12 = 15 × 4 on solving R = 10 Ω

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