NTA Abhyas JEE Main2020PhysicsCurrent ElectricityPractice
The ammeter reading in the given circuit is
Options
- A14 33 A
- B15 32 A
- C17 33 A
- D15 31 A
Correct answer
B. 15 32 A
Step-by-step solution
E e q = 3 × 1 + 6 × 2 1 + 2 = 5 V , r e q = 2 × 1 2 + 1 = 2 3 Ω I = 5 10 + 2 / 3 = 15 32 A