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NTA Abhyas JEE Main2020PhysicsCurrent ElectricityPractice

In the given circuit, the voltmeter reading is 4.5 V . Assuming that the voltmeter is ideal, current through 12 Ω resistance is -

Options

  1. A1 A
  2. B0.5 A
  3. C0.25 A
  4. D0.1 A

Correct answer

B. 0.5 A

Step-by-step solution

The voltmeter is ideal so it doesn't draw any current from the circuit. Potential difference across 9   Ω resistance = 4.5   V (given) So the current in the 9   Ω resistance = 4.5 9 = 0.5   A i.e., I 1 ′ = 0.5   A The same current I 1 ′ passes through 3   Ω . The resistors 9   Ω and 3   Ω are in series and their equivalent, i.e., 12   Ω is in parallel with 6   Ω between A and B . Dividing the current in the inverse

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