NTA Abhyas JEE Main2020PhysicsCurrent ElectricityPractice
In the circuit shown, the heat produced in 5 Ω resistance due to current through it is 50 J s - 1 . Then, the heat generated per second in the 2 Ω resistance is
Options
- A5   J   s - 1
- B4   J   s - 1
- C9   J   s - 1
- D10   J   s - 1
Correct answer
A. 5   J   s - 1
Step-by-step solution
Power is given as, P = 50   J   s - 1 P = Vi                 ⇒ P = i 2 R ⇒ i 2 2 = P R = 50 5 = 10   A 2 V = i 2 R 5   Ω =   10 × 5 =   250   V and 2   Ω and 8   Ω are in series. So, the required resistance = 2   Ω + 8   Ω = 10   Ω i 1 = V R 10   Ω i 1 = 250 10   A The heat generated per second in 2   Ω is given by, P = Vi 1 = i 1 2 × R = 25