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When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be 540 cm . If the balancing length becomes 500 cm when the cell is short-circuited with 1 Ω , the internal resistance of the cell (in Ω ) is

Correct answer

0.08

Step-by-step solution

Internal resistance, r = R l 1 - l 2 l 2 = 1 540 - 500 500 = 40 500 = 0.08 Ω

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