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NTA Abhyas JEE Main2020PhysicsCurrent ElectricityPractice

The figure shown below, calculate the net current from the battery and net resistance of the circuit.

Options

  1. A1 .33 A , 15 2 Ω
  2. B1 .33   A ,   15   Ω
  3. C1 .5   A ,   10   Ω
  4. D1 .5   A ,   15   Ω

Correct answer

A. 1 .33 A , 15 2 Ω

Step-by-step solution

In the given circuit, B and E are at the same potential. Points C and F are also at the same potential. Therefore, the resistance between B and E , C and F will be ineffective and neglected. Now, the circuit becomes In the above circuit, branch ABCD and AEFD are in the parallel combination. Thus, the net resistance of the circuit. 1 R n e t = 1 5 + 5 + 5 + 1 5 + 5 + 5 = 1 15 + 1 15 = 2 15 ⇒ R n e t = 15 2 Ω ∴ Current, I = V R n e t = 10 15 / 2 = 20 15 = 4 3 = 1 .33 A

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