A metal wire of resistance 3 Ω is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60 o at the center, the equivalent

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A metal wire of resistance 3 Ω is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60 o at the center, the equivalent resistance between these two points will be:

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Correct answer: A. 5 3 Ω

We know, R = 8 l A = 8 l 2 A l = 8 l 2 V o l u m e R &#8733; l 2 if the volume is constant. &#8756; &#160; New resistance = 4 R . R 1 = 4 R 360 &#215; 300 = 10 R 3 R 2 = 4 R 360 &#215; 60 = 2 R 3 &#8756; Equivalent resistance R e q = R 1 R 2 R 1 + R 2 = 10 R 3 &#215; 2 R 3 10 R 3 + 2 R 3 = 5 R 9 = 5 3 &#160; &#937;

A metal wire of resistance 3 Ω is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60 o at the center, the equivalent resistance between these two points will be:

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