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The emf of a cell is 6 V and internal resistance is 0 . 5 k Ω . What will be the reading (in volt) of a voltmeter having an internal resistance of 2 . 5 k Ω?

Correct answer

5

Step-by-step solution

Total resistance = 2.5 + 0.5 = 3.0 k Ω = 3000 Ω ∴ Current, i = 6 3000 A ; Reading of voltmeter = i × 2.5 × 1000 = 6 3000 × 2500 = 5 V

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