NTA Abhyas JEE Main2020PhysicsCurrent ElectricityPractice
A voltmeter of variable ranges 3 V , 15 V , 150 V is to be designed by connecting resistances R 1 , R 2 , R 3 in series with a galvanometer of resistance G = 20 Ω , as shown in the figure. The galvanometer gives full pass through its coil. Then, the resistances R 1 , R 2 and R 3 (in kilo ohms) should be, respectively
Options
- A3 , 12 , 135
- B2.98 , 12 , 135
- C2.98 , 14.98 , 149.98
- D3.86 , 12.55 , 122.97
Correct answer
B. 2.98 , 12 , 135
Step-by-step solution
R = V I g – R g R 1 = 3 I g – R g = 2980 Ω = 2.98 k Ω R 1 + R 2 = 15 I g – R g = 14980 Ω = 14.98 k Ω R 1 + R 2 + R 3 = 150 I g – R g = 149980 Ω = 149.98 k Ω ⇒ R 1 = 2.98 k Ω R 2 = 14.98 – 2.98 = 12 k Ω R 3 = 149.98 – 14.98 = 135 k Ω