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A cell of emf E and internal resistance r is connected in series with an external resistance n r . Then what will be the ratio of the terminal potential difference to emf, if n = 9 .

Correct answer

0.9

Step-by-step solution

i = E n + 1 r V T = i R = i n r =   E n + 1 r ×   n r V T E = n n + 1 = 9 9 + 1 = 0 . 9

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