NTA Abhyas JEE Main2020PhysicsCurrent ElectricityPractice
The internal resistance of the cell shown in the figure is negligible. On closing the key k , the ammeter reading changes from 0.25 A to 5 12 A , then what is the value of resistance R 1 (in ohm)?
Correct answer
15
Step-by-step solution
When k was open Reading of A   = E 10   A   =   0.25 , When k was closed Reading of A   = E 10 + R 1 10 R 1 = 5 12 ⇒   12   5   +   0.5 R 1   = 10 R 1 R 1   =   15   Ω