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When a battery of emf 8 V with internal resistance 0.5 Ω is charged by a 120 V DC supply using a series resistance of 15.5 Ω , then the terminal voltage of the battery is

Options

  1. A11 . 5   V
  2. B20 V
  3. C21 . 5 V
  4. D12 . 3 V

Correct answer

A. 11 . 5   V

Step-by-step solution

Here, emf of the battery = 8   V The internal resistance of the battery, r = 0.5   Ω The voltage of D. C supply = 120   V External resistance, R = 15.5   Ω When the battery of emf 8   V is charged from a DC supply of 120   V , the effective emf in the circular is ε = 120 - 8 = 112   V The total resistance of the circuit = R + r     = 15.5 + 0.5   Ω = 16   Ω ∴       Current in the circuit during charging I = ε R

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