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In the following network, the potential at O is

Options

  1. A4   V
  2. B3  V
  3. C6  V
  4. D4.8  V

Correct answer

D. 4.8  V

Step-by-step solution

Let the potential at O is V 0 . Application of Kirchhoff's first law at junction O gives 8 - V 0 2 = V 0 - 4 4 + V 0 - 2 2 = V 0 - 4 + 2 V 0 - 4 4 4 8 - V 0 2 = V 0 - 4 + 2 V 0 - 4 16 - 2 V 0 = 3 V 0 - 8 16 + 8 = 5 V 0 V 0 = 24 5 = 4 .8   V

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