An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the screen. At time t = 0 , side DC of the loop is at edge of the magnetic field. The induced current i versus time t graph will be as

Step-by-step solution

Let 2a be the side of the triangle and b the length AE. AH AE = GH EC ∴ GH = AH AE EC or GH = b - vt b · a = a - a b vt ∴ FG = 2 GH = 2 a - a b vt Induced emf e = Bv FG = 2 Bv a - a b vt ∴ Induced current i = e R = 2 Bv R a - a b vt or i = k 1 - k 2 t Thus, i-t graph is a straight line with negative slope and positive intercept.