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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Electromagnetic Induction

NTA Abhyas 2020 · Physics · Electromagnetic Induction

A ring of mass 4kg is uniformly charged with a linear charge...

A ring of mass 4kg4kg is uniformly charged with a linear charge density λ=4Ccm−1\lambda = 4C{cm}^{- 1} and kept on a rough horizontal surface with a friction coefficient of μ=π4\mu = \dfrac{\pi}{4}. A time-varying magnetic field B=B0t2B = {B}_{0}{t}^{2} is applied in a circular region of radius a(a<r)perpendiculartotheplaneoftheringasshowninthefigure.Findoutthetimewhentheringjuststartstorotateonthesurface.(takea \left(a < r\right) perpendicular to the plane of the ring as shown in the figure. Find out the time when the ring just starts to rotate on the surface. (takea = 5cm,,g = 10m{s}^{- 2} and {B}_{0} = 125SIunits)<br/><br/><imgalt=""src="https://cdn−question−pool.getmarks.app/ntaabhyas/jeemain/images/460398.JPG"style="width:300px;height:235px;"/>SI units)<br /> <br /> <img alt="" src="https://cdn-question-pool.Quantrex.app/nta_abhyas/jee_main/images/460398.JPG" style="width: 300px; height: 235px;" />

Correct answer

4

Step-by-step solution

Induced electric field,
E(2πr)=dϕdtE ( 2\pi r ) = \dfrac{d \phi}{dt}
E=πa22B0t2πrE = \dfrac{{\pi a}^{2}2{B}_{0}t}{2\pi r}
Torque due to field about centre of ring,
τ1=(qE)r=(λ(2πr))(2πa2B0t2πr)r{τ}_{1} = ( qE ) r = ( \lambda ( 2\pi r ) ) \left(\dfrac{2{\pi a}^{2}{B}_{0}t}{2\pi r}\right)r
The ring starts rotating when,
ττ due to electric field =τ= τ due to friction.
τ1=(μmg)r{τ}_{1} = \left(\mu mg\right)r
Solving,
t=μmg2πa2B0λ=4st = \dfrac{\mu mg}{2{\pi a}^{2}{B}_{0}\lambda} = 4s .
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