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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Electromagnetic Induction

NTA Abhyas 2020 · Physics · Electromagnetic Induction

Consider a thin metallic sheet perpendicular to the plane of the...

Consider a thin metallic sheet perpendicular to the plane of the paper moving with speed vv in a uniform magnetic field BB going into the plane of the paper (see figure). If charge densities σ1{σ}_{1} and σ2{σ}_{2} are induced on the left and right surfaces respectively of the sheet, then (ignore fringe effects)

Consider a thin metallic sheet perpendicular to the plane of the paper moving with speed v in a uniform magnetic field

Options

  1. Aσ1=−ϵ0vB2,σ2=ϵ0vB2{σ}_{1} = \dfrac{- {ϵ}_{0}vB}{2}, {σ}_{2} = \dfrac{{ϵ}_{0}vB}{2}
  2. Bσ1=ϵ0vB,σ2=−ϵ0vB{σ}_{1} = {ϵ}_{0}vB, {σ}_{2} = - {ϵ}_{0}vB
  3. Cσ1=ϵ0vB2,σ2=−ϵ0vB2{σ}_{1} = \dfrac{{ϵ}_{0}vB}{2}, {σ}_{2} = \dfrac{- {ϵ}_{0}vB}{2}
  4. Dσ1=σ2=ϵ0vB{σ}_{1} = {σ}_{2} = {ϵ}_{0}vB

Correct answer

B. σ1=ϵ0vB,σ2=−ϵ0vB{σ}_{1} = {ϵ}_{0}vB, {σ}_{2} = - {ϵ}_{0}vB

Step-by-step solution

σ1=−σ2{σ}_{1} = - {σ}_{2} [due to magnetic force]

E=σε0=vBE = \dfrac{σ}{ε0} = vB

σ=ε0vB\sigma = {ε}_{0}vB
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