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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Electromagnetic Induction

NTA Abhyas 2020 · Physics · Electromagnetic Induction

A uniform circular loop of radius a and resistance& R is pulled at...

A uniform circular loop of radius a and resistance& RR is pulled at a constant velocity vv out of a region of a uniform magnetic field whose magnitude is BB. The plane of the loop and the velocity are both perpendicular to BB. Then the electrical power in the circular loop at the instant when the arc (of the circular loop) outside the region of magnetic field subtends an angle π3\dfrac{π}{3} at the centre of the loop is

A uniform circular loop of radius a and resistance& R is pulled at a constant velocity v out of a region of a uniform

Options

  1. AB2a2v2R\dfrac{B^{2}a^{2}v^{2}}{R}
  2. B2B2a2v2R\dfrac{2B^{2}a^{2}v^{2}}{R}
  3. CB2a2v22R\dfrac{B^{2}a^{2}v^{2}}{2R}
  4. Dnone of these

Correct answer

A. B2a2v2R\dfrac{B^{2}a^{2}v^{2}}{R}

Step-by-step solution

The induced emf in the circular loop =B(PQ)v=Bav= B\left(PQ\right)v = Bav

Therefore electrical power consumed by the circular loop

=(emf)2R=(Bav)2R= \dfrac{\left(emf\right)^{2}}{R} = \dfrac{\left(Bav\right)^{2}}{R}

A uniform circular loop of radius a and resistance& R is pulled at a constant velocity v out of a region of a uniform
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