NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
A uniform circular loop of radius a and resistance R is pulled at a constant velocity v out of a region of a uniform magnetic field whose magnitude is B . The plane of the loop and the velocity are both perpendicular to B . Then the electrical power in the circular loop at the instant when the arc (of the circular loop) outside the region of magnetic field subtends an angle π 3 at the centre of the loop is
Options
- AB 2 a 2 v 2 R
- B2 B 2 a 2 v 2 R
- CB 2 a 2 v 2 2 R
- Dnone of these
Correct answer
A. B 2 a 2 v 2 R
Step-by-step solution
The induced emf in the circular loop = B PQ v = Bav Therefore electrical power consumed by the circular loop = emf 2 R = Bav 2 R