NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
A conducting ring of circular cross-section with inner and outer radii a and b is made out of a material of resistivity ρ . The thickness of the ring is h . It is placed coaxially in a vertical cylindrical region of a magnetic field B = krt , where k is a positive constant, r is the distance from the axis and t is the time. If the current through the ring is I = kh αp b 3 - a 3 , then what is the value of α ?
Correct answer
9
Step-by-step solution
The flux through the area of radius r is ϕ = ∫ 0 r k r t 2 π r d r = 2 π k t r 3 3   E.M.F. induced, ϵ = dϕ dt = 2 πkr 3 3 Net induced current is I = ∫ a b 2 πr 3 khdr 3 ρ 2 πr = kh 9 ρ   b 3 - a 3 ∴      α = 9