NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
Magnetic flux ϕ linked with a stationary loop of resistance R varies with time t as ϕ = a t ( T – t ) . The amount of heat generated in the loop, during the time interval T , is
Options
- Aa T 3 R
- Ba 2 T 2 3 R
- Ca 2 T 2 R
- Da 2 T 3 3 R
Correct answer
D. a 2 T 3 3 R
Step-by-step solution
| E | = d ϕ d t = ( a T – 2 a t ) H = ∫ E 2 R d t = a 2 R ∫ 0 T T - 2 t 2 d t = a 2 R ∫ 0 T T 2 + 4 t 2 - 4 T t d t = a 2 R T 2 t 0 T + 4 3 t 3 0 T - 2 T t 2 0 T = a 2 T 3 3 R