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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Mechanical Properties of Solids

NTA Abhyas 2020 · Physics · Mechanical Properties of Solids

There is no change in the volume of a wire due to the change in its...

There is no change in the volume of a wire due to the change in its length on stretching. The Poisson's ratio of the material of the wire is

Options

  1. A+12+ \dfrac{1}{2}
  2. B−12- \dfrac{1}{2}
  3. C+14+ \dfrac{1}{4}
  4. D−14- \dfrac{1}{4}

Correct answer

B. −12- \dfrac{1}{2}

Step-by-step solution

Volume of cylindrical wire, V=\pir2L4V = \dfrac{{\pir}^{2}L}{4}, where xx is the diameter of wire.Differentiating both sides,dVdx=π4[2xL+x2⋅dLdx]Also,volumeremainsconstant\dfrac{dV}{dx} = \dfrac{\pi}{4} \left[2xL + x^{2} ⋅ \dfrac{dL}{dx}\right]Also, volume remains constant∴ dVdx=0∴2xL+x2dLdx=0⟹2xL=−x2dLdx\dfrac{dV}{dx} =0 ∴ 2xL + x^{2}\dfrac{dL}{dx} =0 ⟹ 2xL = - x^{2}\dfrac{dL}{dx}⟹ dxxdLL=−12Poisson′sratio\dfrac{dxx}{dLL} = - \dfrac{1}{2}Poisson's ratio= - 12\dfrac{1}{2}
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