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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Mechanical Properties of Solids

NTA Abhyas 2020 · Physics · Mechanical Properties of Solids

The length of a metal wire is l _ 1 when the tension in it is T _ 1...

The length of a metal wire is l1{l}_{1} when the tension in it is T1{T}_{1} and is l2{l}_{2} when the tension is T2{T}_{2}. The natural length of wire is

Options

  1. Al1+l22\dfrac{{l}_{1} + {l}_{2}}{2}
  2. Bl1l2\sqrt{{l}_{1}{l}_{2}}
  3. Cl1T2−l2T1T2−T1\dfrac{{l}_{1}{T}_{2} - {l}_{2}{T}_{1}}{{T}_{2} - {T}_{1}}
  4. Dl1T2+l2T1T2+T1\dfrac{{l}_{1}{T}_{2} + {l}_{2}{T}_{1}}{{T}_{2} + {T}_{1}}

Correct answer

C. l1T2−l2T1T2−T1\dfrac{{l}_{1}{T}_{2} - {l}_{2}{T}_{1}}{{T}_{2} - {T}_{1}}

Step-by-step solution

Let the original length be ll.

In first case,

l1=l+dl1{l}_{1} = l + d{l}_{1}

Using Hooke's law, x=TKx = \dfrac{T}{K}

Where, xx is the displacement.

We have, l1=l+T1K{l}_{1} = l + \dfrac{{T}_{1}}{K}... (i)

Similarly, l2=l+T2K{l}_{2} = l + \dfrac{{T}_{2}}{K}... (ii)

Solving Equations. (i) and (ii), we get

l=l1T2−l2T1T2−T1l = \dfrac{{l}_{1}{T}_{2} - {l}_{2}{T}_{1}}{{T}_{2} - {T}_{1}}
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