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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Mechanical Properties of Solids

NTA Abhyas 2020 · Physics · Mechanical Properties of Solids

A wire of cross-sectional area A is stretched horizontally between...

A wire of cross-sectional area AA is stretched horizontally between two clamps loaded at a distance 2l2l metres from each other. A weight ww kg suspended from the midpoint of the wire. The strain produced in the wire, (if the vertical distance through which the midpoint of the wire moves down x<lx < l) will beA wire of cross-sectional area A is stretched horizontally between two clamps loaded at a distance 2l metres from each

Options

  1. Ax2l2\dfrac{x2}{l2}
  2. B2x2l2\dfrac{2x^{2}}{l2}
  3. Cx22l2\dfrac{x2}{2l^{2}}
  4. Dx2l\dfrac{x}{2l}

Correct answer

C. x22l2\dfrac{x2}{2l^{2}}

Step-by-step solution

From figure the increase in length ∆l=(PR+RQ)−PQ∆ l = \left(PR + RQ\right) - PQ

= 2PR – PQ

=2(l2+x2)1/2−2l=2l(1+x2l2)1/2−2l= 2{\left(l^{2} + x^{2}\right)}^{1 / 2} - 2l = 2l{\left(1 + \dfrac{x^{2}}{l^{2}}\right)}^{1 / 2} - 2l

=2l[1+12x2l2]−2l= 2l\left[1 + \dfrac{1}{2}\dfrac{x^{2}}{l^{2}}\right] - 2l ( By Binomial theorem)

=x2/l= x^{2} / l

∴Strain=∆l/2l=x2/2l2∴ Strain = ∆ l / 2l = x^{2} / 2l^{2}

A wire of cross-sectional area A is stretched horizontally between two clamps loaded at a distance 2l metres from each
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