NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice
A man in a balloon throws a stone downwards with a speed of 5 m s - 1 with respect to the balloon which is moving upwards with a constant acceleration of 5 m s - 2 . Find the velocity (in m s - 1 ) of the stone relative to the man after 2 s . (Take g = 10 m s - 2 )
Correct answer
35
Step-by-step solution
Relative velocity of stone = 5 m s - 1 relative acceleration of stone = 10 + 5 = 15 m s - 2 v = u + at = 5 + 15 × 2 = 35 m s - 1 relative velocity after t = 2 s is 35 m s - 1