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NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Physics
Chapter: Motion in One Dimension

NTA Abhyas 2020 · Physics · Motion in One Dimension

The x and y coordinates of a particles at any time t are given by x...

The

x

and

y

coordinates of a particles at any time

t

are given by

x = 7t + 4t^{2}

and

y = 5t

. where

x

and

y

are in metre and

t

in second. The acceleration of particle at

t = 5s

is

Options

Azero
B $8ms^{- 2}$
C $20ms^{- 2}$
D $40ms^{- 2}$

Correct answer

B. $8ms^{- 2}$

Step-by-step solution

a = \sqrt{{a}_x^{2} + {a}_y^{2}}

= \left[{\left(\dfrac{d^{2} \text{x}}{{dt}^{2}}\right)}^{2} + {\left(\dfrac{d^{2} \text{y}}{{dt}^{2}}\right)}^{2}\right] \dfrac{1}{2}

Hence,

a = \dfrac{d^{2}x}{dt^{2}} = 8ms^{- 2}

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