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NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice

An athlete, initially at rest, takes 2 s to reach his maximum speed of 36 km h - 1 . The magnitude of his average acceleration (in m s -2 ) is

Correct answer

5

Step-by-step solution

The final speed of the athlete, v = 36 km h - 1 = 36 × 5 18 = 10 m s - 1 initial speed, u = 0 time taken t = 2 s for average acceleration, a v = u + a t a = v - u t = 10 - 0 2 = 5 m s - 2

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