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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Motion in One Dimension

NTA Abhyas 2020 · Physics · Motion in One Dimension

A helicopter takes off along the vertical with an acceleration a =...

A helicopter takes off along the vertical with an acceleration a=3ms−2a = 3m{s}^{- 2} and zero initial velocity. In a certain time t1{t}_{1}, the pilot switches off the engine. At the point of take-off, the sound dies away in time t2=30s{t}_{2} = 30s. Determine the velocity vv of the helicopter (in ms−1m{s}^{- 1}) at the moment when its engine is switched off, assuming that the velocity cc of sound is 320ms−1320m{s}^{- 1}.

Correct answer

80

Step-by-step solution

t2=t1+at122c{t}_{2} = {t}_{1} + \dfrac{a{t}_{1}^{2}}{2c}

t1=(ca)2+2cat2−ca{t}_{1} = \sqrt{{\left(\dfrac{c}{a}\right)}^{2} + \dfrac{2c}{a}{t}_{2}} - \dfrac{c}{a}

v=at1=a[(ca)2+2ct2a−ca]v = a{t}_{1} = a\left[\sqrt{{\left(\dfrac{c}{a}\right)}^{2} + \dfrac{2c{t}_{2}}{a}} - \dfrac{c}{a}\right]

=c2+2act2−c=80ms−1= \sqrt{{c}^{2} + 2ac{t}_{2}} - c = 80m{s}^{- 1}
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