A particle is projected from the ground and simultaneously a wedge starts moving towards the right, as shown in the figure. The maximum height of the wedge for which the particle will not hit the wedge is& $\left[g = 10{ms}^{- 2}\right]$

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A particle is projected from the ground and simultaneously a wedge starts moving towards the right, as shown in the figure. The maximum height of the wedge for which the particle will not hit the wedge is&

\left[g = 10{ms}^{- 2}\right]

Quantrex Academy · Accepted Answer

Correct answer: A. (28)/(9)m

Initial velocities of the particle u _ x = 10 53 = 6m/s u _ y = 10 53 = 8m/s 6t = 1 + t + x. (3)/(5) [where x is the length of the hypotenuse of the wedge] 5t = 1 + (3x)/(5) (in x - direction) 8t - 5t^ 2 = 4. (x)/(5) (in y - direction) x = (35)/(9)m Height = (35)/(9) × (4)/(5) = (28)/(9)m

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