NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice
A particle is projected from the ground and simultaneously a wedge starts moving towards the right, as shown in the figure. The maximum height of the wedge for which the particle will not hit the wedge is g = 10   ms - 2
Options
- A28 9   m
- B28 3   m
- C7 3   m
- D7 4   m
Correct answer
A. 28 9   m
Step-by-step solution
Initial velocities of the particle u x = 10 cos 53 = 6 m/s u y = 10 sin 53 = 8 m/s 6 t = 1 + t + x . 3 5 [where x is the length of the hypotenuse of the wedge] 5 t = 1 + 3 x 5 (in x - direction) 8 t - 5 t 2 = 4 . x 5 (in y - direction) x = 35 9 m Height = 35 9 × 4 5 = 28 9 m