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NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Physics
Chapter: Motion in Two Dimensions

NTA Abhyas 2020 · Physics · Motion in Two Dimensions

Time taken by the projectile to reach from A to B is t . Then the...

Time taken by the projectile to reach from $A$ to $B$ is $t$ . Then the distance $AB$ is equal to

Options

A $\dfrac{ut}{3}$
B $\dfrac{\sqrt{3}ut}{2}$
C $\sqrt{3}ut$
D $2ut$

Correct answer

A. $\dfrac{ut}{3}$

Step-by-step solution

Horizontal component of velocity

{u}_{H} = {u \cos 60}^{o} = \dfrac{\text{u}}{2}

∴ \text{AC} = \left({u}_{H}\right) \text{t} = \dfrac{\text{u} \text{t}}{2}

Time taken by the projectile to reach from A to B is t . Then the distance AB is equal to

and

AB = ACsec30 °

= \left(\dfrac{\text{ut}}{2}\right) \left(\dfrac{2}{\sqrt{3}}\right) = \dfrac{\text{ut}}{\sqrt{3}}

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