NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice
Time taken by the projectile to reach from A to B is t . Then the distance AB is equal to
Options
- Aut 3
- B3 ut 2
- C3 ut
- D2 ut
Correct answer
A. ut 3
Step-by-step solution
Horizontal component of velocity u H = u cos 60 o = u 2 ∴ AC = u H t = u t 2 and AB = AC sec 30 ° = ut 2 2 3 = ut 3