A small body is released from point A of smooth parabolic path y = x 2 , where y is vertical axis and x is horizontal axis at ground, as shown. The body leaves the surface from point B . If g = 10 m s - 2 then what is the value of d (in m )?

Step-by-step solution

H 1 = ( 2 ) 2 = 2 m H 2 = ( 1 ) 2 = 1 m ∴ v = 2 × g × H 2 - H 1 v = 20 m s - 1 tan ⁡ θ = d y dx x = 1 = 2 x x = 1 = 2 - H 2 = d tan ⁡ θ - g d 2 2 u 2 cos 2 ⁡ θ - 1 = 2 d - 10 d 2 2 20 2 1 5 2 5 4 d 2 - 2 d - 1 = 0 On solving we get d = 2 m