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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Motion in Two Dimensions

NTA Abhyas 2020 · Physics · Motion in Two Dimensions

A particle is projected towards the north with speed 20(m)/(s) at...

A particle is projected towards the north with speed 20ms20\dfrac{m}{s} at an angle 45o{45}^{o} with horizontal. Ball gets horizontal acceleration of 7.5ms27 . 5\dfrac{m}{{s}^{2}} towards east due to wind. Range of ball (in meter) minus 42m42m will be

Correct answer

8

Step-by-step solution

Time of flight : T=2usinθg=22sT = \dfrac{2usin \theta}{g} = 2\sqrt{2}s
Range (along north) =u2sin⁡2θg=40m= \dfrac{{u}^{2}\sin 2\theta}{g} = 40m
Range (along east) =12aT2=30m= \dfrac{1}{2}a{T}^{2} = 30m
∴∴ Range =302+402=50m= \sqrt{{30}^{2} + {40}^{2}} = 50m
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