NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice
A particle is projected towards the north with speed 20 m s at an angle 45 o with horizontal. Ball gets horizontal acceleration of 7 . 5 m s 2 towards east due to wind. Range of ball (in meter) minus 42 m will be
Correct answer
8
Step-by-step solution
Time of flight : T = 2 u sin θ g = 2 2 s Range (along north) = u 2 sin 2 θ g = 40 m Range (along east) = 1 2 a T 2 = 30 m ∴ Range = 30 2 + 40 2 = 50 m