A particle is projected from the earth's surface with a velocity of 50 m s - 1 at an angle θ with the horizontal. After 2 s it just clears a wall 5 m high. What is the value of 55 sin θ ? ( g = 10 m s - 2 )

Step-by-step solution

Using equation of motion in y-dir s = u t + 1 2 a t 2 Height after 2   s , h = 5 = 50 sin θ t - 1 2 g t 2 5 = 50 sin θ 2 - 1 2 · 10 · 2 2 25 100 = sin θ sin θ = 1 4 55 sinθ = 55 4 = 13 . 75