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NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice

A particle is projected at an angle of 60 ° above the horizontal with a speed of 10 m s - 1 . After some time the direction of its velocity makes an angle of 30 ° above the horizontal. The speed of the particle at this instant is

Options

  1. A5 3    m  s - 1
  2. B5 3 m s - 1
  3. C5 m s - 1
  4. D10 3   m   s - 1

Correct answer

D. 10 3   m   s - 1

Step-by-step solution

Let v be the velocity of point where it make angle 30 ο with horizontal thus , horizontal velocity remains uncharged, so v cos 30 ο = 10 cos 60 ο v 3 2 = 10 2 v = 10 3   m   s - 1

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