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NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice

A particle is thrown over a triangle from one end of a horizontal base and after grazing the vertex falls on the other end of the base. If α and β be the base angles and θ be the angle of projection. Find the value of tan θ .

Options

  1. Atan α + tan β
  2. Bsin α + sin β
  3. Ctan α + sin β
  4. Dcos α + cos α

Correct answer

A. tan α + tan β

Step-by-step solution

The situation is shown in diagram tan α + tan β = y x + y R - x tan α + tan β = yR x R - x ...(i) Equation of trajectory is y = x tan θ 1 - x R or, tan θ = yR x R - x ...(ii) From Eqs. (i) and (ii), we have tan θ = tan α + tan β

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