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A mass M attached to a spring oscillates with a period of 2 s . If the mass is increased by 2 kg the period increases by one sec. Find the initial mass M (In kg ) assuming that Hooke’s Law is obeyed.

Correct answer

1.6

Step-by-step solution

T = 2 π M K or T ∝ M , T 2 T 1 = M 2 M 1 ∴ 3 2 = M + 2 M Solving this equation we get, M = 1.6 kg .

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