A uniform rod of length 2.0 m is suspended through its endpoint about which it performs small angular oscillations in the vertical plane. Its time period is nearly

Step-by-step solution

It is a physical pendulum, and its time period T = 2 π I m g x here I = moment of inertia of the pendulum about point of suspension I = M L 2 12 + M L 2 4 = M L 2 3 and x = distance of point of suspension from its COM. x = L/2 ⇒ T = 2 π M L 2 / 3 m g L / 2 = 2 π 2 L 3 g ⇒ T = 2 π 2 × 2 3 × 10 = 2. 3  sec .