NTA Abhyas JEE Main2020PhysicsOscillationsPractice
The time period of a simple pendulum is T 1 when its point of suspension is at rest with respect to the ground. When the point of suspension moves vertically upwards according to the law y = k t 2 where k = 1   ms - 2 , its new time period is T 2 , then the value of T 1 2 T 2 2 is [ Take g = 10   ms - 2 ]
Options
- A4 5
- B6 5
- C5 6
- D1
Correct answer
B. 6 5
Step-by-step solution
Acceleration of the point of suspension a = d 2 y d t 2 = 2 k = 2 m / s 2 T = 2 π L g e f f ⇒ T 1 = 2 π L g T 2 = 2 π L g + 2 T 1 2 T 2 2 = g + 2 g = 10 + 2 10 = 6 5