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At a certain place, the acceleration due to gravity is determined using a simple pendulum. The length of the pendulum is 25 . 0   cm and a stopwatch with least count of 1   s measures the time taken by the pendulum for 40 oscillations to be 50   s . The accuracy in the measurement of g is

Options

  1. A4 . 40 %
  2. B3 . 40 %
  3. C2 . 40 %
  4. D5 . 40 %

Correct answer

A. 4 . 40 %

Step-by-step solution

ΔT T = 1 2 Δg g + ΔL L Δg g = 2 ΔT T + ΔL L ;    = 2 1 50 + 0 . 1 25 . 0 = 4 . 4 %

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